document.write( "Question 1105014: A population of bacteria doubles every 18 hours. Initially, the population of bacteria is 50.\r
\n" ); document.write( "\n" ); document.write( "What is the population of the bacteria after 60 hours?\r
\n" ); document.write( "\n" ); document.write( " then round to the nearest whole number
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Algebra.Com's Answer #719771 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
A=Aoe^kt
\n" ); document.write( "A/Ao=2=e^kt
\n" ); document.write( "ln 2=kt
\n" ); document.write( "t=18
\n" ); document.write( "therefore, k=ln2/18=0.0385
\n" ); document.write( "A=50*e^(0.0385*60)=503.72 or 504.
\n" ); document.write( "Check
\n" ); document.write( "After 18 hours the population is 100.
\n" ); document.write( "After 36 hours, 200
\n" ); document.write( "After 54 hours 400
\n" ); document.write( "After 72 hours 800.
\n" ); document.write( "\"graph%28300%2C300%2C-50%2C80%2C-100%2C1000%2C50%2Ae%5E%280.0385x%29%29\"
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