document.write( "Question 1104951: Find the number of possible values of p so that \"+6x%5E2%2Bpx%2B12+\" can be factored as the product of two integral first degree polynomials. \n" ); document.write( "
Algebra.Com's Answer #719686 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\"6%28x%5E2%2B%28p%2F6%29x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Just the quadratic factor
\n" ); document.write( "\"%28x%2B1%29%28x%2B2%29\"
\n" ); document.write( "This takes care of the leading term and the constant term in the quadratic factor.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B3x%2B2=x%5E2%2Bpx%2F6%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "This means that \"3=p%2F6\"
\n" ); document.write( "\"highlight%28p=18%29\"
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