document.write( "Question 1104926: A painter can finish a painting job 2 hours longer than his fellow-painter. After painting for one hour, his fellow-painter joined him and they finished the job in 3 hours. How long will it take each working alone to finish the job? \n" ); document.write( "

Algebra.Com's Answer #719678 by jorel1380(3719) $\"\"$ $\"About$

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Let the first painter's time be n. Then his partner's time is n-2. So:
\n" ); document.write( "1/n+3/n+3/(n-2)=1
\n" ); document.write( "n-2+3n-6+3n=n²-2n
\n" ); document.write( "7n-8=n²-2n
\n" ); document.write( "n²-9n+8=0
\n" ); document.write( "(n-8)(n-1)=0
\n" ); document.write( "n=8 or 1
\n" ); document.write( "Discarding the value of 1, we get the first painter's time as 8 hours working alone, and his fellow-painter's time as 6 hours
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