document.write( "Question 1104881: In the figure given below, triangle BAC is inscribed in a semi circle with BC = 73. Semi circles are constructed outside the triangle, with diameter AB = 48 and AC = 55. Find the area of the shaded region inside the two smaller semi circles but outside the larger circle.\r
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\n" ); document.write( "(please disregard the measurements given in the figure (3 cm and 4 cm) and follow whats stated on the word problem above)\r
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Algebra.Com's Answer #719601 by KMST(5328)\"\" \"About 
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You could calculate the shaded area as
\n" ); document.write( "the sum of the areas of the two small semicircles,
\n" ); document.write( "minus the ate of the large semicircle,
\n" ); document.write( "plus the area of the triangle.
\n" ); document.write( "The area of the triangle is
\n" ); document.write( "\"base%2Aheight%2F2=55%2A48%2F2=1320\"
\n" ); document.write( "because AB and AC are perpendicular,
\n" ); document.write( "so we can take one as the base of the triangle,
\n" ); document.write( "and the other one would be the height.
\n" ); document.write( "We could calculate the areas of the semicircles,
\n" ); document.write( "but we do not need to, because we know ABC is a right triangle.
\n" ); document.write( "The Pythagorean theorem says that the sum of
\n" ); document.write( "the areas of the squares built on the legs of a right triangle
\n" ); document.write( "are equal to the area of the square built on the hypotenuse.
\n" ); document.write( "It works for semicircles too,
\n" ); document.write( "so as you add the areas of the two smaller semicircles,
\n" ); document.write( "you get the area of the large one,
\n" ); document.write( "and when you subtract it you get zero,
\n" ); document.write( "Just before you add the area of the triangle.
\n" ); document.write( "In the end, the shaded area is equal to the area of the triangle:
\n" ); document.write( "\"highlight%281320%29\" area units.
\n" ); document.write( "If you have to show your work,
\n" ); document.write( "and the teacher insists on calculating the area of the semicircles,
\n" ); document.write( "the area of a circle is \"pi%2Aradius%5E2=pi%2Adiameter%5E2%2F4\" .
\n" ); document.write( "So, the area of a semicircle is \"pi%2Adiameter%5E2%2F8\" .
\n" ); document.write( "For the small semicircles the areas are
\n" ); document.write( "\"pi%2A48%5E2%2F8\" and \"pi%2A55%5E2%2F8\" .
\n" ); document.write( "For the large semicircles, the area is
\n" ); document.write( "\"pi%2A73%5E2%2F8\" .
\n" ); document.write( "The area of the shaded region is
\n" ); document.write( "
\n" ); document.write( "Of course, \"48%5E2%2B55%5E2=73%5E2\" , because ABC is a right triangle.
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