document.write( "Question 1104857: The diagonal of a rectangle measures 6sqrt(2) inches. If the width is 8 inches less than the length, then find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #719569 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The length, width, and diagonal of the rectangle form a right triangle.

\n" ); document.write( "Let the length be x and the width x-8; then the Pythagorean Theorem tells us

\n" ); document.write( "\"x%5E2+%2B+%28x-8%29%5E2+=+%286%2Asqrt%282%29%29%5E2\"
\n" ); document.write( "\"x%5E2%2Bx%5E2-16x%2B64+=+72\"
\n" ); document.write( "\"2x%5E2-16x-8+=+0\"
\n" ); document.write( "\"x%5E2-8x-4+=+0\"
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\n" ); document.write( "The length of the rectangle is \"x+=+4%2B2%2Asqrt%285%29\"; the width is \"x-8+=+-4%2B2%2Asqrt%285%29\".

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