document.write( "Question 98784: solve the equation for x\r
\n" ); document.write( "\n" ); document.write( "2(x-5)^2 =3 \n" ); document.write( "

Algebra.Com's Answer #71955 by malakumar_kos@yahoo.com(315) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " solve the equation for x\r
\n" ); document.write( "\n" ); document.write( "2(x-5)^2 =3\r
\n" ); document.write( "\n" ); document.write( " 2(x-5)^2 = 3\r
\n" ); document.write( "\n" ); document.write( " 2(x^2-10x+25) = 3\r
\n" ); document.write( "\n" ); document.write( " 2x^2-20x+50-3 = 0\r
\n" ); document.write( "\n" ); document.write( " 2x^2-20x+47 = 0\r
\n" ); document.write( "\n" ); document.write( " compare with std form we get a= 2 , b= -20 and c = 47
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " substituting for a,b and c we get , \r
\n" ); document.write( "\n" ); document.write( " x = -(-20)+-sq.rt (-20)^2-4.2.47/2.2\r
\n" ); document.write( "\n" ); document.write( " = 20 +-sq.rt 400-376/4
\n" ); document.write( " = 20+-sq.rt 24/4
\n" ); document.write( " = 20+-2.sq.rt6/4
\n" ); document.write( " = 2(10+-sq.rt 6)/4
\n" ); document.write( " = (10+-sq.rt 6)/2
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