document.write( "Question 1104835: In 21 years kayleen will be four times older Han she is today. What is her current age.
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Algebra.Com's Answer #719524 by Alan3354(69443)\"\" \"About 
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In 21 years kayleen will be four times older Han she is today. What is her current age.
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\n" ); document.write( "4x older = 5 times as old.
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\n" ); document.write( "1 time older = 100% older
\n" ); document.write( "2 times older = 200% older
\n" ); document.write( "3 times older = 300% older
\n" ); document.write( "4 times older = 400% older = 5 times as old.
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\n" ); document.write( "K = her age
\n" ); document.write( "K + 21 = 5K
\n" ); document.write( "4K = 21
\n" ); document.write( "K = 5.25 years of age.
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\n" ); document.write( "\"current age\" is redundant.
\n" ); document.write( "Ask \"What is her age?\" as in, \"How old is she?\"
\n" ); document.write( "No need to say \"current\"
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\n" ); document.write( "PS It's disappointing that other tutors seem to think 4 times older is the same as 4 times as old.\r
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