document.write( "Question 98787: solve the quadratic equation by completing the square\r
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document.write( "x^2 - 6x - 3=0 \n" );
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Algebra.Com's Answer #71952 by malakumar_kos@yahoo.com(315)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " solve the quadratic equation by completing the square \n" ); document.write( "x^2 - 6x - 3=0 \n" ); document.write( " \n" ); document.write( " x^2-6x-3 = 0 reduce it to the std form i.e a^2+2ab+b^2 = (a+b)^2\r \n" ); document.write( "\n" ); document.write( " x^2-2.3x = 3 compare with the std form we get 2ab = 2.3x so a= x & b = 3\r \n" ); document.write( "\n" ); document.write( " add (b)^2 = (3)^2 on both sides\r \n" ); document.write( "\n" ); document.write( " x^2- 2.3x+(3)^2 = 3+(3)^2\r \n" ); document.write( "\n" ); document.write( " (x-3)^2 = 3+9\r \n" ); document.write( "\n" ); document.write( " (x-3)^2 = 12\r \n" ); document.write( "\n" ); document.write( " taking sq.rt on both sides \r \n" ); document.write( "\n" ); document.write( " (x-3) = +-sq.rt 12\r \n" ); document.write( "\n" ); document.write( " x = +-2 sq.rt3 +3\r \n" ); document.write( "\n" ); document.write( " required solution is x = 3+-2 (sq.rt 3) \n" ); document.write( " |