document.write( "Question 98797This question is from textbook Geometry
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document.write( ": The measure of the supplemnt of an angle is 60 less than 3 times the measure of the compliment of the angle. Find the measure of the angle. \n" );
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Algebra.Com's Answer #71948 by malakumar_kos@yahoo.com(315) ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " The measure of the supplemnt of an angle is 60 less than 3 times the measure of the compliment of the angle. Find the measure of the angle.\r \n" ); document.write( "\n" ); document.write( " Let the measure of the angle be = x\r \n" ); document.write( "\n" ); document.write( " its supplement will be = 180-x\r \n" ); document.write( "\n" ); document.write( " its compliment will be = 90-x\r \n" ); document.write( "\n" ); document.write( " relation given is (supplement) = 3(90-x)-60\r \n" ); document.write( "\n" ); document.write( " 180-x = 270-3x-60\r \n" ); document.write( "\n" ); document.write( " 3x-x = 270-180-60 \n" ); document.write( " 2x = 270-240 \n" ); document.write( " 2x = 30 \n" ); document.write( " x = 30/2 = 15 \n" ); document.write( " the measure of the angle = 15 degrees \n" ); document.write( " \n" ); document.write( " |