document.write( "Question 1104764: The probability that a certain production process will produce a defective part is 0.20. If a box contains 12 parts, the probability that there will be 6 or 7 defective parts is ? \n" ); document.write( "
Algebra.Com's Answer #719475 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this is a binomial probability type problem.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the process will produce a defective part is .2.\r
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\n" ); document.write( "\n" ); document.write( "this makes p = .2\r
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\n" ); document.write( "\n" ); document.write( "q is the probability that the process will not produce a defective part.\r
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\n" ); document.write( "\n" ); document.write( "the probability of that is equal to 1 - .2 = .8\r
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\n" ); document.write( "\n" ); document.write( "this makes q = .8\r
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\n" ); document.write( "\n" ); document.write( "the formula for binomial probability is p(x) = p^x * q^(n-x) * c(n,x)\r
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\n" ); document.write( "\n" ); document.write( "c(n,x) is equal to n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "it's the number of ways you can get sets of x out of a set of n when the order of the elements within the set is not important.\r
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\n" ); document.write( "\n" ); document.write( "so, your formula is p(x) = p^x * q^(n-x) = c(n,x).\r
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\n" ); document.write( "\n" ); document.write( "n is equal to 12.\r
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\n" ); document.write( "\n" ); document.write( "when x is equal to 6, the formula becomes p(6) = (.2)^2 * (.8)^6 * c(12,6).\r
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\n" ); document.write( "\n" ); document.write( "when x is equal to 7, the formula becomes p(7) = (.2)^7 * (.8)^5 * c(12,7).\r
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\n" ); document.write( "\n" ); document.write( "evaluate these equations and you get:\r
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\n" ); document.write( "\n" ); document.write( "p(6) = .0155021476\r
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\n" ); document.write( "\n" ); document.write( "p(7) = .0033218888\r
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\n" ); document.write( "\n" ); document.write( "add them together and the probability of getting 6 or 7 defective parts is equal to .0188240364.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the probability of getting 6 or 7 defective parts out of a batch of 12 parts is equal to .0188240364.\r
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\n" ); document.write( "\n" ); document.write( "the following excel spreadsheet printout shows all the probabilities and confirms that the sum of all the probabilities must be equal to 1 and also confirms that the answer is correct.\r
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