document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104757>Question 1104757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A type of gunpowder is produced by using 15 parts by weight of nitre to 3 parts of charcoal and 2 parts of sulphur.  Find number of lbs. of nitre used in making 1 ton of the powder.\r<BR>\n" );
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document.write( "My partial solution;\r<BR>\n" );
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document.write( "Let n = nitre<BR>\n" );
document.write( "Let c = charcoal<BR>\n" );
document.write( "Let s = sulphur\r<BR>\n" );
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document.write( "20 parts total.\r<BR>\n" );
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document.write( "1 ton = 2000 lbs.\r<BR>\n" );
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document.write( "Not sure how to proceed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719463 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of elements by weight is 15:3:2. So, for every 20 lbs of gun powder, you have 15 lbs nitre, 3 lbs charcoal, and 2 lbs of sulfur. One ton of powder is 2000 lbs. So:<BR>\n" );
document.write( "2000/20=100<BR>\n" );
document.write( "This breaks down into:<BR>\n" );
document.write( "15x100, or 1500 lbs nitre, 300 lbs charcoal, and 200 lbs sulfur per ton<BR>\n" );
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