document.write( "Question 98815: the length of a rectangle is 4 more than twice the width. the perimeter is 28cm. What are the measures \n" ); document.write( "

Algebra.Com's Answer #71939 by anjali_yamini(27) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " LET :
\n" ); document.write( " THE LENGTH OF THE RECTANGLE = L
\n" ); document.write( " THE WIDTH OF THE RECTANGLE = W
\n" ); document.write( " THE PERIMETR OF THE RECTANGLE = P = 28\r
\n" ); document.write( "\n" ); document.write( " WE KNOW THAT P = L +L + W +W
\n" ); document.write( " P = 2(L+W)
\n" ); document.write( " 28 =2(L+W)\r
\n" ); document.write( "\n" ); document.write( " SINCE L = 4W
\n" ); document.write( " 28 = 2( 4W+W)
\n" ); document.write( " 28 = 2*5W
\n" ); document.write( " 28 = 10W
\n" ); document.write( " 28/10 = W
\n" ); document.write( " 2.8 = W\r
\n" ); document.write( "\n" ); document.write( " L = 4W
\n" ); document.write( " L= 4*2.8
\n" ); document.write( " L = 11.2\r
\n" ); document.write( "\n" ); document.write( " SO, THE DIMENSIONS OF THE RECTANGLE ARE 2.8 IN. AND 11.2 IN.\r
\n" ); document.write( "\n" ); document.write( " CHECK :\r
\n" ); document.write( "\n" ); document.write( " P = L+L+W+W = 2(L+W)
\n" ); document.write( " P = 2(11.2+2.8)
\n" ); document.write( " P = 2*14
\n" ); document.write( " P = 28
\n" ); document.write( "
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