document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104672>Question 1104672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the values of x and y in parallelogram PQRS. PT=y,TR=5x+1,QT=2y,TS=6x+10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719387 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=\"black\" face=\"times\" size=\"3\"><BR>\n" );
document.write( "The point T isn't mentioned. However, I'm assuming that T is the intersection of the two diagonals PR and QS. \r<BR>\n" );
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document.write( "If that assumption is correct, then the diagonals bisect each other. This means they cut each other in half.\r<BR>\n" );
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document.write( "The diagonal PR is cut into PT and TR, both of which are congruent or equal. So PT = TR.\r<BR>\n" );
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document.write( "Similarly, the other diagonal QS is split in half as well. The two equal pieces are QT and TS. So QT = TS.\r<BR>\n" );
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document.write( "We're given<BR>\n" );
document.write( "PT=y,TR=5x+1,QT=2y,TS=6x+10\r<BR>\n" );
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document.write( "Plug those values into the equations set up in the previous section to get\r<BR>\n" );
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document.write( "PT = TR<BR>\n" );
document.write( "y = 5x+1<BR>\n" );
document.write( "and<BR>\n" );
document.write( "QT = TS<BR>\n" );
document.write( "2y = 6x+10\r<BR>\n" );
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document.write( "Start with 2y = 6x+10<BR>\n" );
document.write( "Replace every y with 5x+1. We can do this because y = 5x+1 was found earlier (based on PT = TR)\r<BR>\n" );
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document.write( "So,<BR>\n" );
document.write( "2y = 6x+10<BR>\n" );
document.write( "2( y ) = 6x+10<BR>\n" );
document.write( "2( 5x+1 ) = 6x+10<BR>\n" );
document.write( "2*5x+2*1 = 6x+10<BR>\n" );
document.write( "10x+2 = 6x+10<BR>\n" );
document.write( "10x+2-6x = 6x+10-6x<BR>\n" );
document.write( "4x+2 = 10<BR>\n" );
document.write( "4x+2-2 = 10-2<BR>\n" );
document.write( "4x = 8<BR>\n" );
document.write( "4x/4 = 8/4<BR>\n" );
document.write( "x = 2\r<BR>\n" );
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document.write( "If x = 2, then y is...<BR>\n" );
document.write( "y = 5x+1<BR>\n" );
document.write( "y = 5*x+1<BR>\n" );
document.write( "y = 5*2+1<BR>\n" );
document.write( "y = 10+1<BR>\n" );
document.write( "y = 11\r<BR>\n" );
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document.write( "In summary:<BR>\n" );
document.write( "<font color=red size=4>x = 2 and y = 11</font><BR>\n" );
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