document.write( "Question 1104642: Find all solutions in the interval [0, 2π).\r
\n" ); document.write( "\n" ); document.write( "cos^2(x) + 2 cos x + 1 = 0\r
\n" ); document.write( "\n" ); document.write( "Find all solutions in the interval [0, 2π). \r
\n" ); document.write( "\n" ); document.write( "(sin x)(cos x) = 0\r
\n" ); document.write( "\n" ); document.write( "Find all solutions to the equation.\r
\n" ); document.write( "\n" ); document.write( "cos^2(x) + 2 cos x + 1 = 0
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Algebra.Com's Answer #719382 by Alan3354(69443)\"\" \"About 
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Find all solutions in the interval [0, 2π).\r
\n" ); document.write( "\n" ); document.write( "cos^2(x) + 2 cos x + 1 = 0
\n" ); document.write( "(cos(x) + 1)^2 = 0
\n" ); document.write( "cos(x) = -1
\n" ); document.write( "x = pi radians
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\n" ); document.write( "Find all solutions in the interval [0, 2π). \r
\n" ); document.write( "\n" ); document.write( "(sin x)(cos x) = 0
\n" ); document.write( "sin(x) = 0
\n" ); document.write( "x = 0, pi
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\n" ); document.write( "cos(x) = 0
\n" ); document.write( "x = pi/2, 3pi/2\r
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