document.write( "Question 1104642: Find all solutions in the interval [0, 2π).\r
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document.write( "cos^2(x) + 2 cos x + 1 = 0\r
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document.write( "Find all solutions in the interval [0, 2π). \r
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document.write( "(sin x)(cos x) = 0\r
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document.write( "Find all solutions to the equation.\r
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document.write( "cos^2(x) + 2 cos x + 1 = 0 \n" );
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Algebra.Com's Answer #719382 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find all solutions in the interval [0, 2π).\r \n" ); document.write( "\n" ); document.write( "cos^2(x) + 2 cos x + 1 = 0 \n" ); document.write( "(cos(x) + 1)^2 = 0 \n" ); document.write( "cos(x) = -1 \n" ); document.write( "x = pi radians \n" ); document.write( "========================= \n" ); document.write( "Find all solutions in the interval [0, 2π). \r \n" ); document.write( "\n" ); document.write( "(sin x)(cos x) = 0 \n" ); document.write( "sin(x) = 0 \n" ); document.write( "x = 0, pi \n" ); document.write( "------ \n" ); document.write( "cos(x) = 0 \n" ); document.write( "x = pi/2, 3pi/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |