document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104667>Question 1104667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> $5850 is invested at 9.5% compounded continuously. How long will it take for the balance to reach $11700. Please round your answer to two decimal places, if necessary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719359 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719359\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Poe^rt is the formula, P principal end, Po principal beginning, r is rate (decimal) and t time in years<BR>\n" );
document.write( "11700=5850*e^(.095*t)<BR>\n" );
document.write( "divide by 5850 both sides<BR>\n" );
document.write( "2=e^.095t<BR>\n" );
document.write( "ln both sides<BR>\n" );
document.write( "ln2=0.095 t<BR>\n" );
document.write( "divide by 0.095 both sides <BR>\n" );
document.write( "7.30 years. ANSWER<BR>\n" );
document.write( "Rule of 70 would say doubling occurs when  rate (per cent)*time=70<BR>\n" );
document.write( "That is an approximation but holds here.<BR>\n" );
document.write( " </SPAN>\n" );
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