document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104573>Question 1104573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have one last question on my homework and I can’t seem to figure it out.<BR>\n" );
document.write( "I’ll send the full question and show you what I did throughout. \r<BR>\n" );
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document.write( "9. The first two terms of an infinite geometric sequence, in order, are 2log(sub2)x, log(sub2)x, where x > 0.\r<BR>\n" );
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document.write( "a. Find r. \r<BR>\n" );
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document.write( "For this, I did log(sub2)x/2log(sub2)x = 1/2\r<BR>\n" );
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document.write( "b. Show that the sum of an infinite sequence is 4log(sub2)x. <BR>\n" );
document.write( "I used a1/(1-r) which was 2log(sub2)x/(1-1/2) = 4log(sub2)x\r<BR>\n" );
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document.write( "c. The first three terms of an arithmetic sequence, in order, are log(sub2)x, log(sub2)x/2,log(sub2)x/4<BR>\n" );
document.write( "Find d, giving your answer as an integer. <BR>\n" );
document.write( "(All the ones below are going to be log(sub2), but I’ll fight them as log so it won’t be as messy. <BR>\n" );
document.write( "Logx/2=logx-log2=logx-1<BR>\n" );
document.write( "Logx/4=logx-log4=logx-2<BR>\n" );
document.write( "D=-2\r<BR>\n" );
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document.write( "d. Let S(sub12) be the sum of the first 12 terms of the arithmetic sequence. Show that S(sub12)=12log(sub2)x-66. \r<BR>\n" );
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document.write( "(I did this part but it’s a lot and would take a long time to type out)\r<BR>\n" );
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document.write( "e. THE PART I NEED HELP ON, :)<BR>\n" );
document.write( "given that S(sub12) is equal to half the sum of the infinite geometric sequence, find x, giving your answer in the form 2^p, where p has the domain of Q. \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719335 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13196)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "It seems this part is easier than most of the other parts, if I read it correctly.<br><BR>\n" );
document.write( "We have an infinite geometric series with a sum of 4*log2(x); and we have the sum of 12 terms of an arithmetic series with a sum of 12*log2(x)-66; and we are supposed to solve for x if the sum of the arithmetic series is half the sum of the geometric series:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2Alog2%28x%29-66+=+2%2Alog2%28x%29 ALIGN=MIDDLE  ALT=\"12%2Alog2%28x%29-66+=+2%2Alog2%28x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%2Alog2%28x%29+=+66 ALIGN=MIDDLE  ALT=\"10%2Alog2%28x%29+=+66\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log2%28x%29+=+6.6 ALIGN=MIDDLE  ALT=\"log2%28x%29+=+6.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+2%5E6.6 ALIGN=MIDDLE  ALT=\"x+=+2%5E6.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
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