document.write( "Question 1104623: The perimeter of a rectangle is 12 CM the length is 1 cm shorter than twice the width find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #719323 by ikleyn(52873)\"\" \"About 
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document.write( "L      + W + L      + W = 12\r\n" );
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document.write( "(2W-1) + W + (2W-1) + W = 12\r\n" );
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document.write( "6W - 2 = 12  ====>  6W = 12+2 = 14  ====>  W = \"14%2F6\" = \"7%2F3\" cm.\r\n" );
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document.write( "Answer.  W = \"7%2F3\" cm,  L = \"14%2F3-1\" = \"11%2F3\" cm.\r\n" );
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