document.write( "Question 1104608: Please help me solve this problem...im dying i need this today ... thank you\r
\n" ); document.write( "\n" ); document.write( "Reliie invests 12,000. A part of it earns 10% interest annually and the rest earns 9% interest annually. His annual income from his investments is 1,130. How much is invested at each rate?
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Algebra.Com's Answer #719312 by Gerwally(2)\"\" \"About 
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If x=amount invested at 10%, then 12,000-x=amount invested at 9%
\n" ); document.write( "Then .10x + .09 (12,000-x) = 1130
\n" ); document.write( ".10x + 1080 - .09x = 1130
\n" ); document.write( ".01x. = 1130 - 1080
\n" ); document.write( ".01x = 50
\n" ); document.write( "X = 5000
\n" ); document.write( "12,000 - 5000 = 7000
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