document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104594>Question 1104594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y^-4 = 1/25 and y<0, then y^3 - y = ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719304 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If y^-4 = 1/25 and y<0, then y^3 - y = ? <BR>\n" );
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document.write( "(y^-4)^(-1/4) = (1/25)^(-1/4)<BR>\n" );
document.write( "y = (1/5)^2 ^(-1/4) = (1/5)^-1/2 = (5)^(1/2) = sqrt(5)<BR>\n" );
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document.write( "Ans: y^3 - y = 5^(3/2) - 5^(1/2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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