document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104565>Question 1104565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation. Show algebraic work that fully supports your answer. Exact answers only, no decimal approximations.\r<BR>\n" );
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document.write( "log4(2&#119909;) &#8722; log4(&#119909; &#8722; 3) = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719276 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log 4 {(2x)/(x-3) }=1<BR>\n" );
document.write( "raise everything to the 4<BR>\n" );
document.write( "that becomes 2x/(x-3)=4<BR>\n" );
document.write( "2x=4x-12<BR>\n" );
document.write( "-2x=-12<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "log 4(12)-log4(3)=1 checks since log 4 (12/3)=1 </SPAN>\n" );
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