document.write( "Question 1104503: what are the dimension of the largest rectangular field that can be enclosed with 60 meter of wire \n" ); document.write( "
Algebra.Com's Answer #719261 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "Let the dimensions be L, W, and the area A.\r
\n" ); document.write( "\n" ); document.write( "\"+L+=+%2860-2W%29%2F2+=+30+-+W+\"\r
\n" ); document.write( "\n" ); document.write( "\"+A+=+LW+=+%2830-W%29W++=+30W-+W%5E2+\"
\n" ); document.write( "Take the derivative of A with respect to W:
\n" ); document.write( "\"+dA%2FdW+=+30-2W+\"
\n" ); document.write( "Set it to zero:
\n" ); document.write( "\"++++30-2W+=+0++\" —> \"+W=15m+\" —> \"+L=15m+\"\r
\n" ); document.write( "\n" ); document.write( "To show that's a max, note
\n" ); document.write( "\"+d%5E2A%2FdW%5E2+=+-2+\" which indicates the curve is concave down (hence max at W=L=15)\r
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\n" ); document.write( "Ans: The dimensions of the largest rectangle is 15m x 15m
\n" ); document.write( "( Notice how it is a square that maximizes the area )
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