document.write( "Question 1104537: Give an example of a rational function that fulfills
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\n" ); document.write( "a. A rational function that has a vertical asymptote
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\n" ); document.write( "\n" ); document.write( "b. A rational function that has no vertical asymptote
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\n" ); document.write( "a. A rational function that has a vertical asymptote at -5 and a hole at 7.

\n" ); document.write( "The graph of a rational function has a hole at x=a if there are linear factors of (x-a) in both numerator and denominator.

\n" ); document.write( "The graph of a rational function has a vertical asymptote at x=a if there is a linear factor of x-a in the denominator but not in the numerator.

\n" ); document.write( "So to get a vertical asymptote at x=-5 there must be a factor of (x+5) in the denominator but not in the numerator; to get a hole at x=7 there must be a factor of (x-7) in both numerator and denominator .

\n" ); document.write( "The simplest rational function with those factors is
\n" ); document.write( "\"%28x-7%29%2F%28%28x%2B5%29%28x-7%29%29\"

\n" ); document.write( "b. A rational function that has no vertical asymptote and does have a slant asymptote

\n" ); document.write( "The graph of a rational function has a slant asymptote if the degree of the numerator is 1 greater than the degree of the denominator.

\n" ); document.write( "Assuming for simplicity that there are no holes in the graph, caused by identical linear factors in both numerator and denominator, then if the graph of a rational function has NO vertical asymptotes, then there are no linear factors in the denominator. That means the denominator has no real zeros.

\n" ); document.write( "So a rational function that has a slant asymptote but no vertical asymptote must have a denominator with no real zeros, and a numerator with degree 1 greater than the degree of the denominator.

\n" ); document.write( "A simple example of such a function is
\n" ); document.write( "\"x%5E3%2F%28x%5E2%2B1%29\"
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