document.write( "Question 98831: find the value of Y so that the line through (-2,-1) and (10,y) is perpendicular to the line through (6,-2) and (5,7)\r
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Algebra.Com's Answer #71924 by malakumar_kos@yahoo.com(315)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " find the value of Y so that the line through (-2,-1) and (10,y) is perpendicular to the line through (6,-2) and (5,7)\r
\n" ); document.write( "\n" ); document.write( " When two lines are perpendicular the product of their slopes =-1\r
\n" ); document.write( "\n" ); document.write( " slope of line through (-2,-1) and (10,y) = y-(-1)/10-(-2)
\n" ); document.write( " m = y+1/10+2
\n" ); document.write( " = (y+1)/12\r
\n" ); document.write( "\n" ); document.write( " slope of line through (6,-2) and (5,7) = (7-(-2))/5-6\r
\n" ); document.write( "\n" ); document.write( " M = 7+2/-1
\n" ); document.write( " = -9\r
\n" ); document.write( "\n" ); document.write( " m.M = -1
\n" ); document.write( " (y+1).(-9)/12 = -1
\n" ); document.write( " (y+1) = -1.12/-9
\n" ); document.write( " y+1 = 4/3
\n" ); document.write( " y = 4/3-1
\n" ); document.write( " = 4-3/3 = 1/3\r
\n" ); document.write( "\n" ); document.write( " value of y = 1/3
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