document.write( "Question 1104505: When Lucy married 18 yrs ago her husband to be was three times her age, and today he's twice her age, how old was she when she married him? \n" ); document.write( "

Algebra.Com's Answer #719222 by Edwin McCravy(20060) $\"\"$ $\"About$

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document.write( "L = Lucy's age now\r\n" );
document.write( "L-18 = Lucy's age 18 years ago\r\n" );
document.write( "H = Husband's age now\r\n" );
document.write( "H-18 = Husband's age 18 years ago.\r\n" );
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\n" ); document.write( "When Lucy married 18 yrs ago her husband to be was three times her age
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document.write( " H-18 = 3(L-18)\r\n" );
document.write( "

\n" ); document.write( "and today he's twice her age,
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document.write( "    H = 2L\r\n" );
document.write( "Substitute 2L for H in\r\n" );
document.write( " H-18 = 3(L-18)\r\n" );
document.write( "2L-18 = 3(L-18)\r\n" );
document.write( "2L-18 = 3L-54\r\n" );
document.write( "   -L = -36\r\n" );
document.write( "    L = 36\r\n" );
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document.write( "H = 2L\r\n" );
document.write( "H = 2(36)\r\n" );
document.write( "H = 72\r\n" );
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\n" ); document.write( "how old was she when she married him?
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document.write( " L-18 = Lucy's age 18 years ago (when she married)\r\n" );
document.write( "36-18 = 18\r\n" );
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document.write( "Lucy was 18 when she married and was very foolish \r\n" );
document.write( "at 18 to marry a man 54, don't you think?\r\n" );
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document.write( "Edwin

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