document.write( "Question 1104462: Prove the identity:\r
\n" ); document.write( "\n" ); document.write( "1+cosx/sinx = cscx + cotx
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Algebra.Com's Answer #719218 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The identity as you show it is NOT true: \"1%2Bcosx%2Fsinx+=+cscx+%2B+cotx\"

\n" ); document.write( "If you correctly use parentheses to show the identity, then it is true: \"%281%2Bcosx%29%2Fsinx+=+cscx+%2B+cotx\"

\n" ); document.write( "I will assume that you are submitting all of the large number of similar problems I see here waiting to be answered.

\n" ); document.write( "You won't learn anything by having us do all of these for you. You need to do them yourself.

\n" ); document.write( "I will do this one more for you. But you should be somewhat ashamed to have asked it, since this one is trivial.

\n" ); document.write( "The general method for all the proofs is the same:
\n" ); document.write( "(1) Get everything in terms of sine and cosine -- most of the identities you use will involve sines and cosines. Sometimes (as in this case) just this one step will complete the proof.
\n" ); document.write( "(2) If more is needed, look for a commonly used identity to change the form of the expression you are working on. Probably 90% of the time, the identity you will use is sinx^2+cosx^2 = 1.

\n" ); document.write( "And don't forget that you should only work on one side to make it look like the other side....

\n" ); document.write( "Okay, so here is this one....

\n" ); document.write( "Work on the right hand side to make it look like the left hand side:
\n" ); document.write( "\"cscx+%2B+cotx\"

\n" ); document.write( "= \"%281%2Fsinx%29+%2B+%28cosx%2Fsinx%29\" [basic definitions]

\n" ); document.write( "= \"%281%2Bcosx%29%2Fsinx\" [common denominator]

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