document.write( "Question 1104494: There are twenty coins consisting of dimes and quarters. If the dimes were quarters and the quarters were dimes, he would have 90 cents more than what he has now. Has many dimes and quarters does he have? \n" ); document.write( "
Algebra.Com's Answer #719215 by ikleyn(52908)\"\" \"About 
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document.write( "D + Q = 20.\r\n" );
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document.write( "25D + 10Q = 10D + 25Q + 90\r\n" );
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document.write( "D + Q = 20,\r\n" );
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document.write( "15D - 15Q = 90\r\n" );
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document.write( "D + Q = 20\r\n" );
document.write( "D - Q =  6\r\n" );
document.write( "----------------Add the equations\r\n" );
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document.write( "2D = 26  ====>  D = 13.\r\n" );
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document.write( "Answer.  13 dimes and (20-13) = 7 quarters.\r\n" );
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