document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104428>Question 1104428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Theo is renting 2 types of tables for his party. One type seats 4 people and the other seats 6 people. If 36 will be at his party and he rents 7 tables, how many of each table does he rent? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719164 by </B><A HREF=/tutors/aboutme.mpl?userid=amalm06><B>amalm06(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amalm06><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amalm06><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total number of people seated: 4x+6y=36\r<BR>\n" );
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document.write( "The total number of tables: x+y=7\r<BR>\n" );
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document.write( "Solve for x: x=7-y\r<BR>\n" );
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document.write( "4(7-y)+6y=36\r<BR>\n" );
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document.write( "28-4y+6y=36\r<BR>\n" );
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document.write( "2y=8\r<BR>\n" );
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document.write( "y=4\r<BR>\n" );
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document.write( "x=3\r<BR>\n" );
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document.write( "Therefore, he rents 3 tables seating 4 people and 4 tables seating 6 people (Answer) \r<BR>\n" );
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document.write( " </SPAN>\n" );
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