document.write( "Question 1104392: Allison invests a total of $20,000 in two accounts, one paying 5% and the
\n" ); document.write( "other paying 8% simple interest per year. Her annual interest is $1180. How much did she invest at each rate?
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Algebra.Com's Answer #719117 by addingup(3677)\"\" \"About 
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Let the amount at 5% be x
\n" ); document.write( "the amount at 8% is 20000-x
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\n" ); document.write( "0.05x+0.08(20000-x) = 1180
\n" ); document.write( "0.05x+1600-0.08x = 1180
\n" ); document.write( "-0.03x = -420
\n" ); document.write( "x = 14000 this is the amount invested at 5%
\n" ); document.write( "the amount at 8% is: 20000-14000 = 6000
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\n" ); document.write( "check:
\n" ); document.write( "0.05(14000)+0.08(6000) = 700+480 = 1180 Correct
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