document.write( "Question 1104361: A sphere is just inclosed inside the right circular cylinder. If the volume of the gap between cylinder & sphere is 90 cm cube.Find the volume of the sphere.
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Algebra.Com's Answer #719111 by ankor@dixie-net.com(22740)\"\" \"About 
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A sphere is just inclosed inside the right circular cylinder.
\n" ); document.write( " If the volume of the gap between cylinder & sphere is 90 cm cube.
\n" ); document.write( " Find the volume of the sphere.
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\n" ); document.write( "cylinder vol - sphere vol = 90
\n" ); document.write( "(\"pi%2Ar%5E2%2Ah\") - (\"4%2F3\"*\"pi%2Ar%5E3\") = 90
\n" ); document.write( "The radius of the base of the cylinder and the radius of the sphere are the same
\n" ); document.write( "The height of the cylinder = the diameter of the sphere or 2r
\n" ); document.write( "(\"pi%2Ar%5E2%2A2r\") - (\"4%2F3\"*\"pi%2Ar%5E3\") = 90
\n" ); document.write( "(\"pi%2A2r%5E3\") - (\"4%2F3\"*\"pi%2Ar%5E3\") = 90
\n" ); document.write( "factor out \"pi%2Ar%5E3\"
\n" ); document.write( "\"pi%2Ar%5E3\"(\"2+-+4%2F3\") = 90
\n" ); document.write( "\"pi%2Ar%5E3\"(\"2%2F3\") = 90
\n" ); document.write( "multiply both sides b6 3
\n" ); document.write( "\"2%2Api%2Ar%5E3\" = 270
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "\"pi%2Ar%5E3\" = 135
\n" ); document.write( "r = \"3sqrt%28135%2Fpi%29\"
\n" ); document.write( "find the cube root
\n" ); document.write( "r = 3.5026 cm
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\n" ); document.write( "Find the vol of the sphere
\n" ); document.write( "V = (\"4%2F3\"*\"pi%2A3.5026%5E3\")
\n" ); document.write( "V = 180 cu/cm
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\n" ); document.write( "The vol of the cylinder will be 270 cu/cm, interesting relationship!
\n" ); document.write( "see if that checks out
\n" ); document.write( "\"pi%2A3.5026%5E2%2A7.0052\" = 269.99, pretty close\r
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