document.write( "Question 98840This question is from textbook
\n" ); document.write( ": one question: about finding center and radius (circle graph) : \r
\n" ); document.write( "\n" ); document.write( "\"+3x%5E2+%2B+3y%5E2+-+6x+%2B+12y=+0+\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "i did this:\r
\n" ); document.write( "\n" ); document.write( "(3x^2 -6x) + (3y^2 +12y)=0\r
\n" ); document.write( "\n" ); document.write( "then I complete the square:\r
\n" ); document.write( "\n" ); document.write( "-6/2 = -3^2=9 and 12/2 =6^2=36\r
\n" ); document.write( "\n" ); document.write( "then:\r
\n" ); document.write( "\n" ); document.write( "(3x^2-6x+9) + (3y^2+12y+36)= 9+36\r
\n" ); document.write( "\n" ); document.write( "(3x-3)^2 + (3y +6)^2 =45\r
\n" ); document.write( "\n" ); document.write( "factor:\r
\n" ); document.write( "\n" ); document.write( "3(x-1) + 3(y+2)= 45\r
\n" ); document.write( "\n" ); document.write( "i got the answer for center:\r
\n" ); document.write( "\n" ); document.write( "C(1,-2) \r
\n" ); document.write( "\n" ); document.write( "and the answer to the raduis is square root of 5\r
\n" ); document.write( "\n" ); document.write( "which i dont know how they got it.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "thank you\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #71911 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, your error is found in the step...\"completing the square\"
\n" ); document.write( "Let's go over that:
\n" ); document.write( "\"3x%5E2-6x%2B3y%5E2%2B12y+=+0\" then you said ...\"complete the square\", but before you do that, you should factor out a 3 then divide through by 3 and you will get:
\n" ); document.write( "\"3%28x%5E2-2x%2By%5E2%2B4%29+=+0\" Divide both sides by 3.
\n" ); document.write( "\"x%5E2-2x%2By%5E2%2B4y+=+0\" Now you complete the square when the coefficients of the \"x%5E2\" and \"y%5E2\" terms are equal to 1.
\n" ); document.write( "\"%28x%5E2-2x%2B1%29%2B%28y%5E2%2B4y%2B4%29+=+1%2B4\" Factor the trinomials.
\n" ); document.write( "\"%28x-1%29%5E2%2B%28y%2B2%29%5E2+=+5\" Now compare this with the standard form for a circle of radius r and center at (h, k).
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2\"and you can see that h = 1, k = -2, and \"r%5E2+=+5\"
\n" ); document.write( "The center (h, k) is at (1, -2) and the radius is \"r+=+sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );