document.write( "Question 1104320: The sum of three numbers is one hundred. the second number is one more than twice the first number. the third number is three less than the first number. find the three numbers. \n" ); document.write( "
Algebra.Com's Answer #719078 by ankor@dixie-net.com(22740)\"\" \"About 
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The sum of three numbers is one hundred.
\n" ); document.write( "a + b + c = 100
\n" ); document.write( "the second number is one more than twice the first number.
\n" ); document.write( "b = 2a+ 1
\n" ); document.write( "the third number is three less than the first number.
\n" ); document.write( "c = a - 3
\n" ); document.write( " find the three numbers.
\n" ); document.write( "In the 1st equation, replace b with (2a+1)and c with (a-3)
\n" ); document.write( "a + (2a+1) + (a-3) = 100
\n" ); document.write( "combine like terms
\n" ); document.write( "a + 2a + a + 1 - 3 = 100
\n" ); document.write( "4a -2 = 100
\n" ); document.write( "4a = 100 + 2
\n" ); document.write( "4a = 102
\n" ); document.write( "a = 102/4
\n" ); document.write( "a = 25.5
\n" ); document.write( "find b
\n" ); document.write( "b = 2(25.5) + 1
\n" ); document.write( "b = 51 + 1
\n" ); document.write( "b = 52
\n" ); document.write( "find c
\n" ); document.write( "c = 25.5-3
\n" ); document.write( "c = 22.5
\n" ); document.write( ":
\n" ); document.write( "Check, find the sum of these three numbers
\n" ); document.write( "25.5 + 52 + 22.5 = 100
\n" ); document.write( " \n" ); document.write( "
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