document.write( "Question 1104299: If \"+ab%5E2c%5E3=3600+\", where a, b and c are distinct positive integers greater than 1, what is the least possible value of a+b+c? \n" ); document.write( "
Algebra.Com's Answer #719073 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The prime factorization of 3600 is (2^4)(3^2)(5^2).

\n" ); document.write( "If 3600 = ab^2c^3, then c must be 2, because 2 is the only prime factor that occurs 3 or more times.

\n" ); document.write( "That means ab^2 = 2(3^2)(5^2).

\n" ); document.write( "There are only two possibilities:
\n" ); document.write( "(1) b^2=3^2 and a = 2(5^2) = 50; that makes a+b+c = 50+3+2 = 55; or
\n" ); document.write( "(2) b^2=5^2 and a = 2(3^2) = 18; that makes a+b+c = 18+5+2 = 25.

\n" ); document.write( "The minimum value of a+b+c is 25.
\n" ); document.write( "
\n" );