document.write( "Question 1104285: please help me solve this binomial expansiom
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\n" ); document.write( " show that the coefficient of \"a%5E12b%5E3\" in a binomial expansion of \"%28a%2Bb%29%5E15\" is 455. use the the expansion to evaluate\"%281.02%29%5E15\"
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Algebra.Com's Answer #719035 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
show that the coefficient of \"a%5E12b%5E3\" in a binomial expansion of \"%28a%2Bb%29%5E15\" is 455. use the the expansion to evaluate\"%281.02%29%5E15\"
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\n" ); document.write( "a^12*b^3 is in the term (15C12)a^12b^(15-12)
\n" ); document.write( "with coefficient 15C12 = 15!/[(15-12)!*12!] which equals 455
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\n" ); document.write( "1.02^15 = (1+02)^15 = 15C15*1^15*0.02^0 + 15C14*1^14*0.02^1 + 15C13*1^13*0.02^2 +....+ 15C0*1^0*0.02^15
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\n" ); document.write( "1.02^15 = 1*1*1 + 15*1*0.02 + [(15*14)/(1*2)]*1*0.02^2 + ...+ 1*1*3.2768x10^-26
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\n" ); document.write( "= 1.34586...
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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