document.write( "Question 98840This question is from textbook
\n" ); document.write( ": one question: about finding center and radius (circle graph) : \r
\n" ); document.write( "\n" ); document.write( "\"+3x%5E2+%2B+3y%5E2+-+6x+%2B+12y=+0+\"\r
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\n" ); document.write( "\n" ); document.write( "i did this:\r
\n" ); document.write( "\n" ); document.write( "(3x^2 -6x) + (3y^2 +12y)=0\r
\n" ); document.write( "\n" ); document.write( "then I complete the square:\r
\n" ); document.write( "\n" ); document.write( "-6/2 = -3^2=9 and 12/2 =6^2=36\r
\n" ); document.write( "\n" ); document.write( "then:\r
\n" ); document.write( "\n" ); document.write( "(3x^2-6x+9) + (3y^2+12y+36)= 9+36\r
\n" ); document.write( "\n" ); document.write( "(3x-3)^2 + (3y +6)^2 =45\r
\n" ); document.write( "\n" ); document.write( "factor:\r
\n" ); document.write( "\n" ); document.write( "3(x-1) + 3(y+2)= 45\r
\n" ); document.write( "\n" ); document.write( "i got the answer for center:\r
\n" ); document.write( "\n" ); document.write( "C(1,-2) \r
\n" ); document.write( "\n" ); document.write( "and the answer to the raduis is square root of 5\r
\n" ); document.write( "\n" ); document.write( "which i dont know how they got it.\r
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\n" ); document.write( "\n" ); document.write( "thank you\r
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Algebra.Com's Answer #71903 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
the first step in completing the square should be to make the coefficient of the squared term 1\r
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\n" ); document.write( "\n" ); document.write( "in this case, the first step is to factor (reduce) if possible ... dividing by 3 gives x^2+y^2-2x+4y=0\r
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\n" ); document.write( "\n" ); document.write( "completing the square gives x^2-2x+1+y^2+4y+4=5 ... (x-1)^2+(y+2)^2=5\r
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\n" ); document.write( "\n" ); document.write( "if you FOIL (3x-3)^2, you don't get 3x^2-6x+9 ... similarly with (3y+6)^2
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