document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104266>Question 1104266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rationalize the denominator and simplify if possible\r<BR>\n" );
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document.write( "63/ Square root 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #719006 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=719006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rationalize the denominator means to take it out of the square root sign.\r<BR>\n" );
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document.write( "start with 63 / sqrt(7)\r<BR>\n" );
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document.write( "multiply both numerator and denominator by sqrt(7) and you will get 63 * sqrt(7) / 7\r<BR>\n" );
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document.write( "the denominator has now been rationalized.\r<BR>\n" );
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document.write( "since 63 / 7 = 9, then the expression can be simplified to 9 * sqrt(7).\r<BR>\n" );
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document.write( "you can confirm by evaluating the original expression of 63 / sqrt(7) and seeing that the value is that same as 9 * sqrt(7).\r<BR>\n" );
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document.write( "it is.\r<BR>\n" );
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