document.write( "Question 1104242: Find the product (xy) if x+y+\"+sqrt%28+x%2By+%29+\" = 20 and x-y+\"sqrt+%28+x-y+%29+\"=12. \n" ); document.write( "
Algebra.Com's Answer #718992 by ikleyn(52814)\"\" \"About 
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document.write( "It is assumed in the given equations  that  \"sqrt%28x%2By%29\" >= 0  and  \"sqrt%28x-y%29\" >= 0.\r\n" );
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document.write( "1.  Let u = \"sqrt%28x+%2B+y%29\".  Then\r\n" );
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document.write( "    \"u%5E2+%2B+u\" = 20,   or\r\n" );
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document.write( "    \"u%5E2+%2B+u+-+20\" = 0.\r\n" );
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document.write( "    Factor left side\r\n" );
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document.write( "    (u+5)*(u-4) = 0.\r\n" );
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document.write( "    As  just noticed above, \"sqrt%28x%2By%29\" assumed to be >= 0.\r\n" );
document.write( "    Therefore, only positive root  u = 4  works.\r\n" );
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document.write( "    Thus,  \"sqrt%28x%2By%29\" = 4.   Then  x + y = 4^2 = 16.\r\n" );
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document.write( "2.  Similarly, Let v = \"sqrt%28x+-+y%29\".  Then\r\n" );
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document.write( "    \"v%5E2+%2B+v\" = 12,   or\r\n" );
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document.write( "    \"v%5E2+%2B+v+-+12\" = 0.\r\n" );
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document.write( "    Factor left side\r\n" );
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document.write( "    (v+4)*(v-3) = 0.\r\n" );
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document.write( "    As  just noticed above, \"sqrt%28x-y%29\" assumed to be >= 0.\r\n" );
document.write( "    Therefore, only positive root  v = 3  works.\r\n" );
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document.write( "    Thus,  \"sqrt%28x-y%29\" = 3.   Then  x - y = 3^2 = 9.\r\n" );
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document.write( "3.  Thus we have two equations\r\n" );
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document.write( "    x + y = 16,\r\n" );
document.write( "    x - y =  9,\r\n" );
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document.write( "    which implies  x= 12.5,  y= 3.5.\r\n" );
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document.write( "Answer.  The solution is  x= 12.5,  y= 3.5.  The product xy = 43.75.\r\n" );
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