document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1104203>Question 1104203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 11. Let x = ln 3 and y = ln 5. Write the following expressions in terms of x and y. <BR>\n" );
document.write( " <BR>\n" );
document.write( "a. ln(5/3)<BR>\n" );
document.write( "b. ln45 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718934 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718934\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = ln 3 and y = ln 5. Write the following expressions in terms of x and y. <BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Log(a/b) = log(a) - log(b)<BR>\n" );
document.write( "log(a*b) = log(a) + log(b)<BR>\n" );
document.write( " ====================<BR>\n" );
document.write( "a. ln(5/3)<BR>\n" );
document.write( "5/3 = 5/3<BR>\n" );
document.write( "=======<BR>\n" );
document.write( "b. ln45<BR>\n" );
document.write( "45 = 3*3*5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );