document.write( "Question 1104125: suppose the odds against an event are 5:2
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document.write( "a}what are the odds in favor of the event?
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document.write( "b} what is the probabilty of the event? \n" );
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Algebra.Com's Answer #718855 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if odds against are 5:2, then odds in favor are 2:5 and probability against is 5:7 and probability for is 2:7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "basically:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds in favor equals probability for divided by probability against.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds against equals probability against divided by probability for.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds in favor equals reciprocal of odds against.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds against equals reciprocal of odds in favor.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let's say you have 7 marbles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5 of them are white and 2 of them are black.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of drawing a white marble = 5/7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability of drawing a black marble = 2/7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds in favor of drawing a white marble = probability for divided by probability against = (5/7) / (2/7) = (5/7) * (7/2) = (5/2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "odds against drawing a white marble = probability against divided by probability for = (2/7) / (5/7) = (2/7) * (7/5) = (2/5).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |