document.write( "Question 1104087: hi Algebra.Com tutors,\r
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document.write( "thanks for your mathematical services. I have been dealing with permutations for a while, so I'm a genius at solving them, I believe.\r
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document.write( "however, the problem challenging me is working them practically! I solved 3 P 2 (=6) by drawing a table. But 5 P 3 (=60) and 10 P 3 (=720) failed completely!\r
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document.write( "Can you help me with the true table proving the results above?\r
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document.write( "I look forward to hear from you.\r
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document.write( "A. S. B. H. \n" );
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Algebra.Com's Answer #718840 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! You are dealing with permutations where you have n itmes \n" ); document.write( ": \n" ); document.write( "For example 3 P 2 means you have three items from which you are making selections \n" ); document.write( ": \n" ); document.write( "3 P 2 = 3 * (3-1) = 6 (for the first choice you have 3 to pick from, for second choice you have 2 to pick from) \n" ); document.write( ": \n" ); document.write( "5 P 3 = 5 * (5-1) * (5-2) = 60 \n" ); document.write( ": \n" ); document.write( "10 P 3 = 10 * (10-1) * (10-2) = 720 \n" ); document.write( " |