document.write( "Question 98808: Richard has 22 coins with a total value of $4. If the coins are all quarters and dimes, how many of each type of coin does he have? \n" ); document.write( "
Algebra.Com's Answer #71881 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Richard has 22 coins \n" ); document.write( "d + q = 22 \n" ); document.write( "d = (22 - q) \n" ); document.write( ": \n" ); document.write( "with a total value of $4. \n" ); document.write( ".10d + .25q = 4 \n" ); document.write( ": \n" ); document.write( "If the coins are all quarters and dimes, how many of each type of coin does he have? \n" ); document.write( ": \n" ); document.write( "Substitute (22-q) for d in the above equation: \n" ); document.write( ".10(22-q) + .25q = 4 \n" ); document.write( "2.2 - .10a + .25q = 4 \n" ); document.write( "-.10q + .25q = 4 - 2.2 \n" ); document.write( ".15q = 1.8 \n" ); document.write( "q = 1.8/.15 \n" ); document.write( "q = 12 quarters \n" ); document.write( ": \n" ); document.write( "That would give us: 22 - 12 = 10 dimes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions \n" ); document.write( ".10(10) + .25(12) = \n" ); document.write( "1.00 + 3.00 = 4.00 \n" ); document.write( " |