document.write( "Question 1104019: Blake is working his way through school. He works two part-time jobs for a total of
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document.write( "32
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document.write( " hours a week. Job A pays
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document.write( "$6.10\r
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document.write( " per hour, and Job B pays \r
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document.write( "$7.20 per hour. How many hours did he work at each job the week that he made
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document.write( "$211.70\r
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document.write( ". \n" );
document.write( "
Algebra.Com's Answer #718750 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( " x + y = 32 (1) (hours, counting Blake's working hours)\r\n" ); document.write( "6.10*x + 7.20*y = 211.70 (2) (dollars, counting his earnings)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Multiply eq(1) by 6.10 (both sides). The modified (and equivalent) system is THIS:\r\n" ); document.write( "\r\n" ); document.write( "6.10x + 6.10*y = 6.10*32 (3)\r\n" ); document.write( "6.10*x + 7.20*y = 211.70 (4)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now subtract eq(3) from eq(4) (both sides). The terms \"6.10*x\" will cancel each other,\r\n" ); document.write( "and you will get a single equation for only ONE unknown y (it is how the Elimination method works)\r\n" ); document.write( "\r\n" ); document.write( "7.20*y - 6.10*y = 211.70 - 6.10*32,\r\n" ); document.write( "\r\n" ); document.write( "1.10y = 16.5 ====> y =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On the way, you learned on how the Elimination method works.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |