document.write( "Question 1104022: An oil painting is 10 inches longer than it is wide and is bordered on all sides by a 3 inch wide frame. If the area of the frame alone is 402 inches squared, what are the dimensions of the painting? \n" ); document.write( "

Algebra.Com's Answer #718744 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+w+\"$ = the width of the painting
\n" ); document.write( " $\"+w+%2B+10+\"$ = the length of the painting
\n" ); document.write( " $\"+w%2A%28+w+%2B+10+%29+\"$ = the area of the painting
\n" ); document.write( " $\"+%28+w+%2B+6+%29%2A%28+w+%2B+10+%2B+6+%29+\"$ = the area of painting plus frame
\n" ); document.write( "----------------------------------------------------------
\n" ); document.write( " $\"+%28+w+%2B+6+%29%2A%28+w+%2B+16+%29+-+w%2A%28+w+%2B+10+%29+=+402+\"$
\n" ); document.write( " $\"+w%5E2+%2B+6w+%2B+16w+%2B+96+-+w%5E2+-+10w+=+402+\"$
\n" ); document.write( " $\"+12w+=+402+-+96+\"$
\n" ); document.write( " $\"+12w+=+306+\"$
\n" ); document.write( " $\"+w+=+25.5+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+w+%2B+10+=+35.5+\"$ = length of the painting
\n" ); document.write( "--------------------------
\n" ); document.write( "The dimensions are 25.5 x 35.5
\n" ); document.write( "-----------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+w+%2B+6+%29%2A%28+w+%2B+16+%29+-+w%2A%28+w+%2B+10+%29+=+402+\"$
\n" ); document.write( " $\"+25.5+%2B+6+%29%2A%28+25.5+%2B+16+%29+-+25.5%2A35.5+=+402+\"$
\n" ); document.write( " $\"+31.5%2A41.5+-+905.25+-+402+\"$
\n" ); document.write( " $\"+1307.25+-+905.25+=+402+\"$
\n" ); document.write( " $\"+402+=+402+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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