document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1103965>Question 1103965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The L.C.M. of 5/7, 10/9 and 15/11 will be ....... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #718701 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20056)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=718701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since denominators 7,9, and 11 have no common factors<BR>\n" );
document.write( "other than 1, we multiply them together:\r<BR>\n" );
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document.write( "LCM = 7󭘱1 = 693  </SPAN>\n" );
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