document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98763>Question 98763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on solving  3x + 4 = 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71869 by </B><A HREF=/tutors/aboutme.mpl?userid=doukungfoo><B>doukungfoo(195)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=doukungfoo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=doukungfoo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First subtract 4 from both sides of the equation which results in <BR>\n" );
document.write( "3x = 6<BR>\n" );
document.write( "now to solve for x divde both sides of the equation by 3 \r<BR>\n" );
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document.write( "3x + 4 = 10<BR>\n" );
document.write( "3x + 4 - 4 = 10 - 4<BR>\n" );
document.write( "3x = 6<BR>\n" );
document.write( "3x/3 = 6/3\r<BR>\n" );
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document.write( "x = 2\r<BR>\n" );
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