document.write( "Question 1103963: Mercy invested part of her money at 8% per year and twice amount at 5% per year. If the return last year in the two investment was 4200 how much did mercy invest at each rate \n" ); document.write( "

Algebra.Com's Answer #718674 by Theo(13342) $\"\"$ $\"About$

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let x = the amount of money she invested at 8%.
\n" ); document.write( "then 2 * x = the amount of money she invested at 5%.\r
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\n" ); document.write( "\n" ); document.write( ".08 * x + .05 * 2 * x = 4200.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get .08 * x + .10 * x = 4200.\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get .18 * x = 4200.\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by .18 to get x = 23,333.33 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "2x is therefore equal to 46,666.67 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "you get .08 * 23,333.33 + .05 * 46,666.67 = 4200.\r
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\n" ); document.write( "\n" ); document.write( "i used the unrounded numbers to do the calculations.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that she invested 23,333.33 at 8% and 46,666.67 at 5%. \n" ); document.write( "

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