document.write( "Question 1103959: What percentage of the data under a normal curve would indicated between z = -1 and z = 2 ? \n" ); document.write( "
Algebra.Com's Answer #718673 by Theo(13342)![]() ![]() You can put this solution on YOUR website! online calculator says and shows .8186\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://davidmlane.com/hyperstat/z_table.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "table says z = -1 has area to the left of it of .1587. \n" ); document.write( "table says z = 2 has area to the left of it of .9772.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract .1587 from .9772 and the area between z = -1 and 2 shows as .8185\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "my TI-84 plus says .8185946784.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculators are more accurate than the table, so go with .8186.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |