document.write( "Question 1103899: Taylor deposits $3,500 at the end of year 1, $4,000 at the end of year 3 and $2,500 at the end of year 5. If interest is 6.2% compounded monthly, determine the value at the end of year 7 \n" ); document.write( "
Algebra.Com's Answer #718617 by Theo(13342) You can put this solution on YOUR website! 3500 invested at the end of year 1. \n" ); document.write( "4000 invested at the end of year 3. \n" ); document.write( "2500 invested at the end of year 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "what is value at end of year 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the general formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = p * (1 + r/c) ^ (n*c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per year. \n" ); document.write( "n is the number of years. \n" ); document.write( "c is the number of compounding periods per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your future value will be 7 years from today.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you compounding periods per year is equal to 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your yearly interest rate is equal to 6.2% / 100 = .062.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 1, you will invest $3500 for 7 - 1 = 6 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 3, you will invest 4000 for 7 - 3 = 4 years.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 5, you will invest 2500 for 7 - 5 = 2 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your future values will be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 3500 * (1 + .062/12) ^ (6*12) = 5072.36 \n" ); document.write( "f = 4000 * (1 + .062/12) ^ (4*12) = 5122.57 \n" ); document.write( "f = 2500 * (1 + .062/12) ^ (2*12) = 2829.14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your total future value will be $13,024.07\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your monthly cash flow looks like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" );
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