document.write( "Question 1103868: Two ships leave the harbor together traveling on courses that have an angle of 127 degrees between them. If they each travel 519 miles, how far apart are they (to the nearest mile)? \n" ); document.write( "
Algebra.Com's Answer #718600 by ankor@dixie-net.com(22740)\"\" \"About 
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Two ships leave the harbor together traveling on courses that have an angle of 127 degrees between them.
\n" ); document.write( " If they each travel 519 miles, how far apart are they (to the nearest mile)?
\n" ); document.write( ":
\n" ); document.write( "the two sides of 519 mi and the dist between the ships form a scalene triangle
\n" ); document.write( "We can treat this as two equal right triangles where the base is 1/2 the dist between the ships
\n" ); document.write( "let b = the base of the each triangel
\n" ); document.write( "Find the equal angles, 180 - 127 = 53 degrees. Each angle 53/2 = 26.5 degrees
\n" ); document.write( "Use the cosine of 26.5 degrees
\n" ); document.write( "co(26.5) = \"b%2F519\"
\n" ); document.write( "b = cos(26.5) * 519
\n" ); document.write( "b = 464.47 mi therefore
\n" ); document.write( "2(464.47 = 929 mi between the ships
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