document.write( "Question 98530This question is from textbook Algebra structure and Method
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document.write( ": gym is 21 years newer than the auditorium. the gym is also one fourth as old as the auditorium. how old is each building? choices for auditorium age: 26, 27, 28\r
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Algebra.Com's Answer #71856 by edjones(8007)![]() ![]() You can put this solution on YOUR website! g=gym's age a=auditorium's age \n" ); document.write( "a=g+21 \n" ); document.write( "a=4g \n" ); document.write( "replace a with 4g in the 1st equation: 4g=g+21 \n" ); document.write( "subtract g from each side: 3g=21 \n" ); document.write( "divide 3 into each side: g=7 \n" ); document.write( "a=28 \n" ); document.write( "Ed \n" ); document.write( " \n" ); document.write( " |