document.write( "Question 1103832: Charlie invested his savings in two investment funds. The
\n" ); document.write( "$4000
\n" ); document.write( " that he invested in Fund A returned a
\n" ); document.write( "2%
\n" ); document.write( " profit. The amount that he invested in Fund B returned a
\n" ); document.write( "5%
\n" ); document.write( " profit. How much did he invest in Fund B, if both funds together returned a
\n" ); document.write( "3%
\n" ); document.write( " profit?
\n" ); document.write( "

Algebra.Com's Answer #718531 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "NOTE: I misread the problem, thinking that the $4000 was the total amount invested.

\n" ); document.write( "Skip down to the ================= to see the revised solution.

\n" ); document.write( "Here, first, is the quick way to get the answer to a problem like this. We can look at the slow, formal algebraic method later.

\n" ); document.write( "The 3% average return is twice as close to 2% as it is to 5%. That means twice as much was invested at 2% as at 5%.

\n" ); document.write( "That means the $4000 was invested with 2/3 of it at 2% and 1/3 of it at 5%.

\n" ); document.write( "1/3 of $4000 is $1333.33 (which indicates \"bad\" numbers are used for this problem....)
\n" ); document.write( "2/3 of $4000 is $2666.67

\n" ); document.write( "So the amount he invested in Fund B was $1333.33.


\n" ); document.write( "Now the standard algebraic solution method....

\n" ); document.write( "\"The return for x amount in Fund B at 5%, plus the return for the rest (4000-x) in Fund A at 2%, yielded an average return of 3% on the total investment\".
\n" ); document.write( "Translated into an algebraic equation,
\n" ); document.write( "\".05%28x%29%2B.02%284000-x%29+=+.03%284000%29\" [note the form for each term on both sides of the equation is the same: (interest rate)*(amount)]
\n" ); document.write( "\"5%28x%29%2B2%284000-x%29+=+3%284000%29\" [simplify the calculation by getting rid of the decimals]
\n" ); document.write( "\"5x%2B8000-2x+=+12000\"
\n" ); document.write( "\"3x+=+4000\"
\n" ); document.write( "\"x+=+1333.33\"

\n" ); document.write( "The amount invested in Fund B at 5% was $1333.33.

\n" ); document.write( "========================================================================
\n" ); document.write( "Here, first, is the quick way to get the answer to a problem like this. We can look at the slow, formal algebraic method later.

\n" ); document.write( "The 3% average return is twice as close to 2% as it is to 5%. That means twice as much was invested at 2% as at 5%.

\n" ); document.write( "Since twice as much was invested in Fund A as in Fund B, the amount he invested in Fund B was $2000.


\n" ); document.write( "Now the standard algebraic solution method....

\n" ); document.write( "\"The return for x amount in Fund B at 5%, plus the return for the 4000 in Fund A at 2%, yielded an average return of 3% on the total investment\".
\n" ); document.write( "Translated into an algebraic equation,
\n" ); document.write( "\".05%28x%29%2B.02%284000%29+=+.03%284000%2Bx%29\" [note the form for each term on both sides of the equation is the same: (interest rate)*(amount)]
\n" ); document.write( "\"5%28x%29%2B2%284000%29+=+3%284000%2Bx%29\" [simplify the calculation by getting rid of the decimals]
\n" ); document.write( "\"5x%2B8000+=+12000%2B3x\"
\n" ); document.write( "\"2x+=+4000\"
\n" ); document.write( "\"x+=+2000\"

\n" ); document.write( "The amount invested in Fund B at 5% was $2000.

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